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Variance gamma process : ウィキペディア英語版
Variance gamma process

In the theory of stochastic processes, a part of the mathematical theory of probability, the variance gamma process (VG), also known as Laplace motion, is a Lévy process determined by a random time change. The process has finite moments distinguishing it from many Lévy processes. There is no diffusion component in the VG process and it is thus a pure jump process. The increments are independent and follow a Variance-gamma distribution, which is a generalization of the Laplace distribution.
There are several representations of the VG process that relate it to other processes. It can for example be written as a Brownian motion W(t) with drift \theta t subjected to a random time change which follows a gamma process \Gamma(t; 1, \nu) (equivalently one finds in literature the notation \Gamma(t;\gamma=1/\nu,\lambda=1/\nu)):
:
X^(t; \sigma, \nu, \theta) \;:=\; \theta \,\Gamma(t; 1, \nu) + \sigma\,W(\Gamma(t; 1, \nu))
\quad.

An alternative way of stating this is that the variance gamma process is a Brownian motion subordinated to a Gamma subordinator.
Since the VG process is of finite variation it can be written as the difference of two independent gamma processes:
:
X^(t; \sigma, \nu, \theta) \;:=\; \Gamma(t; \mu_p, \mu_p^2\,\nu) - \Gamma(t; \mu_q, \mu_q^2\,\nu)

where
:
\mu_p := \frac\sqrt} + \frac
\quad\quad\text\quad\quad
\mu_q := \frac\sqrt} - \frac
\quad.

Alternatively it can be approximated by a compound Poisson process that leads to a representation with explicitly given (independent) jumps and their locations. This last characterization gives an understanding of the structure of the sample path with location and sizes of jumps.
On the early history of the variance-gamma process see Seneta (2000).〔

== Moments ==
The mean of a variance gamma process is independent of \sigma and \nu and is given by
:E() = \theta t
The variance is given as
:Var() = (\theta^2 \nu + \sigma^2)t
The 3rd central moment is
:E = (2 \theta^3 \nu^2 + 3 \sigma^2 \theta \nu)t
The 4th central moment is
:E = (3 \sigma^4 \nu + 12 \sigma^2 \theta^2 \nu^2 + 6 \theta^4 \nu^3)t + (3 \sigma^4 + 6 \sigma^2 \theta^2 \nu + 3 \theta^4 \nu^2)t^2

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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